Seema takes three beakers A, B and C filled with aqueous solution of glucose, alcohol and hydrochloric acid respectively as shown in the following figure:

(i) State your observation in terms of glowing of bulb when the switch is ON.
(ii) Justify your observations by giving reason for each case.
(iii) Mention the change noticed with appropriate reason if the content of beaker B is replaced by NaOH solution."

i> Bulb A and Bulb B do not glow when the switch is on but Bulb C glows.

ii> Glucose (Beaker A) and Alcohol (Beaker B) do not conduct electricity as they do not dissociate into ions.

Dilute HCl (Beaker C) dissociates to form ions H⁺ and Cl^-, hence the current flows through it and the bulb glows.

$HCl\leftrightarrows \ H^{+} \ +\ Cl^{-}$

 iii> If alcohol is replaced by NaOH solution in the beaker B, then we observe that the bulb Glows in beaker B as NaOH dissociates into ions.

$NaOH\leftrightarrows \ Na^{+} \ +\ OH^{-}$

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Updated on: 10-Oct-2022

Bulb A and Bulb B do not glow when the switch is on but Bulb C glows. ii> Glucose (Beaker A) and Alcohol (Beaker B) do not conduct electricity as they do not dissociate into ions.Dilute HCl (Beaker C) dissociates to form ions H+ and Cl-, hence the current flows through it and the bulb glows.$HCl','sharer','toolbar=0,status=0,width=580,height=325');" href="javascript: void(0)" title="Share on Facebook"> Bulb A and Bulb B do not glow when the switch is on but Bulb C glows. ii> Glucose (Beaker A) and Alcohol (Beaker B) do not conduct electricity as they do not dissociate into ions.Dilute HCl (Beaker C) dissociates to form ions H+ and Cl-, hence the current flows through it and the bulb glows.$HCl','sharer','toolbar=0,status=0,width=580,height=325');" href="javascript: void(0)" title="Share on LinkedIn">

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