$S$ and $T$ are points on sides $PR$ and $QR$ of $∆PQR$ such that $\angle P = \angle RTS$. Show that $∆RPQ \sim ∆RTS$.

AcademicMathematicsNCERTClass 10

Given:

$S$ and $T$ are points on sides $PR$ and $QR$ of $∆PQR$ such that $\angle P = \angle RTS$.

To do:

We have to show that $∆RPQ \sim ∆RTS$.

Solution:


In $\triangle RPQ$ and $\triangle RTS$,

$\angle P=\angle RTS$

$\angle P=\angle R$

Therefore, by AA criterion,

$\Delta RPQ \sim \Delta RTS$

Hence proved.

raja
Updated on 10-Oct-2022 13:21:04

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