Ramkali saved Rs. 5 in the first week of a year and then increased her weekly saving by Rs. 1.75. If in the nth week, her weekly saving become Rs. 20.75, find $n$.
Given:
Ramkali saved Rs. 5 in the first week of a year and then increased her weekly saving by Rs. 1.75.
In the nth week, her weekly saving becomes Rs. 20.75.
To do:
We have to find $n$.
Solution:
Her weekly saving will be an A.P
Let
$a = 5, d = 1.75 , a_n= 20.75$
$a_n = a+(n-1)d$
$5+(n-1)1.75 = 20.75$
$5+1.75n -1.75 = 20.75$
$1.75n= 20.75+1.75-5$
$1.75n= 22.50-5$
$1.75n = 17.50$
$n = \frac{17.50}{1.75}$
$n = 10$
Therefore, the value of $n$ is 10.
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