The Time When the Network Becomes Idle - Problem
Network Message Processing Simulation
Imagine you're managing a distributed server network where server 0 is the master server and servers
Here's how the system works:
• At second 0, all data servers send their first message to the master server
• Messages travel through the shortest path to reach the master server
• The master server processes messages instantly and sends replies back through the same path
• If a data server doesn't receive a reply within its
• Once a server receives its reply, it stops sending messages
Goal: Find the earliest second when the network becomes completely idle (no messages in transit).
Imagine you're managing a distributed server network where server 0 is the master server and servers
1 to n-1 are data servers. The network is connected through message channels defined by edges, where edges[i] = [ui, vi] means servers ui and vi can communicate directly.Here's how the system works:
• At second 0, all data servers send their first message to the master server
• Messages travel through the shortest path to reach the master server
• The master server processes messages instantly and sends replies back through the same path
• If a data server doesn't receive a reply within its
patience[i] seconds, it resends the message• Once a server receives its reply, it stops sending messages
Goal: Find the earliest second when the network becomes completely idle (no messages in transit).
Input & Output
example_1.py — Basic Network
$
Input:
edges = [[0,1],[1,2]], patience = [0,2,1]
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Output:
8
💡 Note:
Server 1 (distance=1): round_trip=2, patience=2, sends at 0,2,4,6. Last reply at 8. Server 2 (distance=2): round_trip=4, patience=1, sends at 0,1,2,3. Last reply at 7. Network idle at max(8,7)+1 = 8.
example_2.py — Star Network
$
Input:
edges = [[0,1],[0,2],[1,3]], patience = [0,10,10,10]
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Output:
3
💡 Note:
All servers have high patience (10), so they only send one message each. Server 3 has the longest path (distance=2), so it takes 4 seconds for round trip. Network idle at 4+1 = 5. Wait, let me recalculate: distance to 3 is 2, round trip is 4, only one message sent, completes at 4, idle at 5.
example_3.py — Minimum Case
$
Input:
edges = [[0,1]], patience = [0,1]
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Output:
3
💡 Note:
Only one data server at distance 1. Round trip = 2, patience = 1. Messages sent at times 0 and 1. Last message (sent at time 1) completes at time 3. Network idle at 4.
Constraints
- n == patience.length
- 2 ≤ n ≤ 105
- patience[0] == 0
- 1 ≤ patience[i] ≤ 105 for i > 0
- 1 ≤ edges.length ≤ min(105, n × (n - 1) / 2)
- edges[i].length == 2
- 0 ≤ ui, vi < n
- ui != vi
- There are no duplicate edges
- Each server computer is directly or indirectly connected to every other server
Visualization
Tap to expand
Understanding the Visualization
1
Build Network Graph
Create connections between servers based on edges
2
Find Shortest Paths
Use BFS to find shortest distance from each server to master
3
Calculate Message Patterns
Determine when each server sends its messages based on patience
4
Find Network Idle Time
Calculate when the last message completes its journey
Key Takeaway
🎯 Key Insight: Instead of simulating every second, calculate mathematically when each server's final message completes its round trip. The network becomes idle one second after the maximum completion time.
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Explanation
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