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Sort a Dictionary by Its Values

Certification: Intermediate Level Accuracy: 41.67% Submissions: 12 Points: 5

Write a Python program that sorts a dictionary by its values in ascending order.

Example 1
    
  
  • Input: {'a': 3, 'b': 1, 'c': 2}
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  • Output: {'b': 1, 'c': 2, 'a': 3}
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  • Explanation: 
    
      
      
    • Step 1: Take the input dictionary {'a': 3, 'b': 1, 'c': 2}.
      • 
      
    • Step 2: Extract the key-value pairs: [('a', 3), ('b', 1), ('c', 2)].
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    • Step 3: Sort the pairs by their values: [('b', 1), ('c', 2), ('a', 3)].
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    • Step 4: Reconstruct the dictionary from the sorted pairs.
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    • Step 5: Return the sorted dictionary {'b': 1, 'c': 2, 'a': 3}.
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Example 2
    
  
  • Input: {'x': 5, 'y': 2, 'z': 8}
    • 
  
  • Output: {'y': 2, 'x': 5, 'z': 8}
    • 
  
  • Explanation: 
    
      
      
    • Step 1: Take the input dictionary {'x': 5, 'y': 2, 'z': 8}.
      • 
      
    • Step 2: Extract the key-value pairs: [('x', 5), ('y', 2), ('z', 8)].
      • 
      
    • Step 3: Sort the pairs by their values: [('y', 2), ('x', 5), ('z', 8)].
      • 
      
    • Step 4: Reconstruct the dictionary from the sorted pairs.
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    • Step 5: Return the sorted dictionary {'y': 2, 'x': 5, 'z': 8}.
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Constraints
    
  
  • 1 ≤ len(d) ≤ 10^3
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  • -10^5 ≤ d[key] ≤ 10^5
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  • Time Complexity: O(n log n), where n is the number of key-value pairs
    • 
  
  • Space Complexity: O(n)
    •
ListDictionaries AccentureSnowflake
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Hint
Solution

Solution Hints

    
  
  • Use the sorted() function with key=lambda to sort by values.
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  • Convert the sorted result to a dictionary using dict().
    • 
  
  • Use items() to get key-value pairs from the dictionary.
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  • Sort based on the second element of each tuple (the value) using key=lambda x: x[1].
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  • Ensure the output maintains the original key-value pairs in sorted order.
    •

Steps to solve by this approach:

 Step 1: Get all (key, value) pairs from the dictionary using items().
 Step 2: Sort these pairs using the sorted() function.
 Step 3: Specify a key function lambda x: x[1] to sort by the second element (value).
 Step 4: Convert the sorted list of tuples back to a dictionary with dict().
 Step 5: This creates a new dictionary ordered by values (ascending).
 Step 6: Return the new dictionary with keys ordered by their values.
 Step 7: Example: {'a': 3, 'b': 1, 'c': 2} becomes {'b': 1, 'c': 2, 'a': 3}.

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