
Problem
Solution
Submissions
Merge Two Dictionaries into One
Certification: Intermediate Level
Accuracy: 0%
Submissions: 0
Points: 5
Write a Python program that merges two dictionaries into one. If there are duplicate keys, the value from the second dictionary should overwrite the value from the first.
Example 1
- Input 1: {'a': 1, 'b': 2}
- Input 2: {'b': 3, 'c': 4}
- Output: {'a': 1, 'b': 3, 'c': 4}
- Explanation:
- Step 1: Take the first dictionary {'a': 1, 'b': 2} and the second dictionary {'b': 3, 'c': 4}.
- Step 2: Create a new dictionary with all key-value pairs from the first dictionary: {'a': 1, 'b': 2}.
- Step 3: Add all key-value pairs from the second dictionary, overwriting any existing keys.
- Step 4: The key 'b' appears in both dictionaries, so its value is updated to 3 from the second dictionary.
- Step 5: Return the merged dictionary {'a': 1, 'b': 3, 'c': 4}.
Example 2
- Input 1: {'x': 5, 'y': 2}
- Input 2: {'y': 8, 'z': 9}
- Output: {'x': 5, 'y': 8, 'z': 9}
- Explanation:
- Step 1: Take the first dictionary {'x': 5, 'y': 2} and the second dictionary {'y': 8, 'z': 9}.
- Step 2: Create a new dictionary with all key-value pairs from the first dictionary: {'x': 5, 'y': 2}.
- Step 3: Add all key-value pairs from the second dictionary, overwriting any existing keys.
- Step 4: The key 'y' appears in both dictionaries, so its value is updated to 8 from the second dictionary.
- Step 5: Return the merged dictionary {'x': 5, 'y': 8, 'z': 9}.
Constraints
- 1 ≤ len(d1), len(d2) ≤ 10^3
- -10^5 ≤ d1[key], d2[key] ≤ 10^5
- Time Complexity: O(n), where n is the total number of key-value pairs
- Space Complexity: O(n)
Editorial
My Submissions
All Solutions
Lang | Status | Date | Code |
---|---|---|---|
You do not have any submissions for this problem. |
User | Lang | Status | Date | Code |
---|---|---|---|---|
No submissions found. |
Solution Hints
- Use the
**
operator to unpack and merge dictionaries. - Use the
update()
method to merge dictionaries in place. - Use dictionary comprehension to combine the dictionaries.