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Count the Number of Digits in an Integer

Certification: Basic Level Accuracy: 62.16% Submissions: 185 Points: 5

Write a Python program that counts the number of digits in a given integer.

Example 1
    
  
  • Input: 12345
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  • Output: 5
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  • Explanation: 
    
      
      
    • Step 1: Take the input number 12345.
      • 
      
    • Step 2: Count the digits: 1, 2, 3, 4, 5.
      • 
      
    • Step 3: Return the count 5.
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Example 2
    
  
  • Input: -9876
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  • Output: 4
    • 
  
  • Explanation: 
    
      
      
    • Step 1: Take the input number -9876.
      • 
      
    • Step 2: Ignore the negative sign and work with 9876.
      • 
      
    • Step 3: Count the digits: 9, 8, 7, 6.
      • 
      
    • Step 4: Return the count 4.
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Constraints
    
  
  • -10^9 ≤ number ≤ 10^9
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  • For negative numbers, ignore the negative sign
    • 
  
  • Time Complexity: O(log n), where n is the input number
    • 
  
  • Space Complexity: O(1)
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ArraysStringsRecursionKPMGDropbox
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Hint
Solution

Solution Hints

    
  
  • Convert to string: len(str(abs(number)))
    • 
  
  • Use logarithm: import math; int(math.log10(abs(number))) + 1 if number != 0 else 1
    • 
  
  • Use iterative counting: count = 0; while abs(number) > 0: count += 1; number //= 10
    • 
  
  • Use recursion: def count_digits(n): return 1 if abs(n) < 10 else 1 + count_digits(abs(n) // 10)
    •

The following are the steps to count the number of digits in an integer:

  •  Take an integer as input.  

  •  Convert it to a string.  

  •  Use `len()` to count the digits.  

  •  Print the count.  

  •  Verify with numbers like `1000`, `-123`, `0`.

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