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Convert a List of Tuples into a Dictionary

Certification: Basic Level Accuracy: 91.43% Submissions: 35 Points: 10

Write a Python program that converts a list of tuples into a dictionary. Each tuple consists of two elements: the first element becomes a key in the dictionary, and the second element becomes its corresponding value.

Example 1
    

  • Input: tuple_list = [("a", 1), ("b", 2), ("c", 3)]
    • 

  • Output: {"a": 1, "b": 2, "c": 3}
    • 

  • Explanation: 
      

    • Step 1: Initialize an empty dictionary.
      • 

    • Step 2: Iterate through each tuple in the input list.
      • 

    • Step 3: For each tuple, use the first element as a key and the second element as its value in the dictionary.
      • 

    • Step 4: For ("a", 1), set key "a" to value 1.
      • 

    • Step 5: For ("b", 2), set key "b" to value 2.
      • 

    • Step 6: For ("c", 3), set key "c" to value 3.
      • 

    • Step 7: Return the resulting dictionary.
      • 

    •
Example 2
    

  • Input: tuple_list = [("apple", 5), ("banana", 7), ("orange", 8), ("apple", 10)]
    • 

  • Output: {"apple": 10, "banana": 7, "orange": 8}
    • 

  • Explanation: 
      

    • Step 1: Initialize an empty dictionary.
      • 

    • Step 2: Iterate through each tuple in the input list.
      • 

    • Step 3: For each tuple, use the first element as a key and the second element as its value in the dictionary.
      • 

    • Step 4: For ("apple", 5), set key "apple" to value 5.
      • 

    • Step 5: For ("banana", 7), set key "banana" to value 7.
      • 

    • Step 6: For ("orange", 8), set key "orange" to value 8.
      • 

    • Step 7: For ("apple", 10), update key "apple" to value 10 (overwriting the previous value).
      • 

    • Step 8: Return the resulting dictionary.
      • 

    •
Constraints
    

  • 1 ≤ len(tuple_list) ≤ 10^5
    • 

  • All keys must be hashable
    • 

  • If there are duplicate keys, the last occurrence's value should be used
    • 

  • Time Complexity: O(n) where n is the number of tuples
    • 

  • Space Complexity: O(n)
    •
Functions / MethodsListTupleDeloitteSnowflake
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Hint
Solution

Solution Hints

    
  
  • Use a dictionary comprehension: {key: value for key, value in tuple_list}
    • 
  
  • Iterate through the list and update the dictionary for each tuple
    • 
  
  • Check if the dictionary already contains a key before adding it
    • 
  
  • If the key already exists, update its value
    • 
  
  • Use the dict() constructor with the list of tuples: dict(tuple_list)
    • 
  
  • Handle edge cases such as empty lists or tuples with more than two elements
    •

Steps to solve by this approach:

 Step 1: Initialize an empty dictionary to store key-value pairs.

 Step 2: Iterate through each tuple in the input list.
 Step 3: Unpack each tuple into key and value components.

 Step 4: Add or update the key-value pair in the dictionary.

 Step 5: Return the completed dictionary.

Submitted Code :