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Check if a Given Year is a Leap Year

Certification: Basic Level Accuracy: 34.31% Submissions: 102 Points: 5

Write a Python program that determines whether a given year is a leap year.

Example 1
    

  • Input: year = 2020
    • 

  • Output: True
    • 

  • Explanation: 
      

    • Step 1: Check if the year is divisible by 4.
      • 

    • Step 2: 2020 is divisible by 4 (2020 ÷ 4 = 505 with no remainder).
      • 

    • Step 3: Check if the year is divisible by 100.
      • 

    • Step 4: 2020 is not divisible by 100 (2020 ÷ 100 = 20.2 with a remainder).
      • 

    • Step 5: Since 2020 is divisible by 4 but not by 100, it is a leap year.
      • 

    • Step 6: Return True.
      • 

    •
Example 2
    

  • Input: year = 1900
    • 

  • Output: False
    • 

  • Explanation: 
      

    • Step 1: Check if the year is divisible by 4.
      • 

    • Step 2: 1900 is divisible by 4 (1900 ÷ 4 = 475 with no remainder).
      • 

    • Step 3: Check if the year is divisible by 100.
      • 

    • Step 4: 1900 is divisible by 100 (1900 ÷ 100 = 19 with no remainder).
      • 

    • Step 5: Since 1900 is divisible by 100, check if it's also divisible by 400.
      • 

    • Step 6: 1900 is not divisible by 400 (1900 ÷ 400 = 4.75 with a remainder).
      • 

    • Step 7: Since 1900 is divisible by 100 but not by 400, it is not a leap year.
      • 

    • Step 8: Return False.
      • 

    •
Constraints
    

  • 1 ≤ year ≤ 10^5
    • 

  • Time Complexity: O(1)
    • 

  • Space Complexity: O(1)
    •
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Hint
Solution

Solution Hints

    
  
  • A year is a leap year if: (year % 400 == 0) or (year % 4 == 0 and year % 100 != 0)
    • 
  
  • Century years must be divisible by 400
    •

The following are the steps to check if a given year is a leap year:

  • Define the function is_leap_year(year).

  • Use the condition (year % 400 == 0) or (year % 4 == 0 and year % 100 != 0).

  • Return True or False based on the condition.

  • Call the function and print the result.

Submitted Code :