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Valid Anagram

Certification: Basic Level Accuracy: 100% Submissions: 1 Points: 5

Write a JavaScript program to determine if two given strings are anagrams of each other. An anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once. For example, "listen" and "silent" are anagrams because they contain the same characters with the same frequency.

Example 1
    
      
  • Input: str1 = "listen", str2 = "silent"
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  • Output: true
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  • Explanation: "listen" contains letters: l, i, s, t, e, n and "silent" contains letters: s, i, l, e, n, t. Both strings have the same characters with the same frequency, therefore they are anagrams of each other.
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Example 2
    
      
  • Input: str1 = "hello", str2 = "world"
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  • Output: false
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  • Explanation: "hello" contains letters: h, e, l, l, o and "world" contains letters: w, o, r, l, d. The strings have different characters and frequencies, therefore they are not anagrams of each other.
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Constraints
    
      
  • 1 ≤ str1.length, str2.length ≤ 5 * 10^4
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  • str1 and str2 consist of lowercase English letters only
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  • Time Complexity: O(n)
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  • Space Complexity: O(1) - considering fixed alphabet size
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StringsKPMGSamsung
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Hint
Solution

Solution Hints

    
      
  • First check if both strings have the same length - if not, they cannot be anagrams
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  • Create a frequency map to count occurrences of each character in the first string
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  • Iterate through the second string and decrement the count for each character
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  • If any character count becomes negative, the strings are not anagrams
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  • Alternatively, you can sort both strings and compare them for equality
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Steps to solve by this approach:

 Step 1: Check if both strings have the same length - if not, return false immediately.
 Step 2: Create an empty object to store character frequencies from the first string.
 Step 3: Iterate through the first string and count the frequency of each character.
 Step 4: Iterate through the second string and decrement the count for each character.
 Step 5: If any character is not found or count becomes negative, return false.
 Step 6: If all characters are matched with correct frequencies, return true.

Submitted Code :