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Maximum and Minimum in Array

Certification: Basic Level Accuracy: 100% Submissions: 1 Points: 5

Write a JavaScript program to find both the maximum and minimum values in an array of numbers. The function should return an object containing both values. Given an array of integers, efficiently determine the largest and smallest numbers without using built-in Math.max() or Math.min() functions.

Example 1
    
      
  • Input: arr = [3, 1, 4, 1, 5, 9, 2, 6]
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  • Output: {max: 9, min: 1}
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  • Explanation: 
    • The array contains numbers: [3, 1, 4, 1, 5, 9, 2, 6]. 
    • Starting with first element 3 as both max and min. 
    • Comparing each element: 1 is smaller than current min (3), so min becomes 1. 
    • Element 4 is between current min (1) and max (3), no change. 
    • Element 5 is greater than current max (4), so max becomes 5. 
    • Element 9 is greater than current max (5), so max becomes 9. 
    • Final result: maximum is 9, minimum is 1.
    •
Example 2
    
      
  • Input: arr = [10, -5, 0, 15, -10, 8]
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  • Output: {max: 15, min: -10}
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  • Explanation: 
    • The array contains numbers: [10, -5, 0, 15, -10, 8]. 
    • Starting with first element 10 as both max and min. 
    • Element -5 is smaller than current min (10), so min becomes -5. 
    • Element 0 is between current min (-5) and max (10), no change. 
    • Element 15 is greater than current max (10), so max becomes 15. 
    • Element -10 is smaller than current min (-5), so min becomes -10. 
    • Element 8 is between current min (-10) and max (15), no change. 
    • Final result: maximum is 15, minimum is -10.
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Constraints
    
      
  • 1 ≤ arr.length ≤ 10^5
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  • -10^9 ≤ arr[i] ≤ 10^9
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  • Array contains at least one element
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  • Time Complexity: O(n) where n is the length of array
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  • Space Complexity: O(1)
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ArraysPwCLTIMindtree
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Hint
Solution

Solution Hints

    
      
  • Initialize both max and min variables with the first element of the array
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  • Start iterating from the second element (index 1) of the array
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  • For each element, compare it with the current maximum value
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  • If current element is greater than max, update the max value
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  • Similarly, compare current element with the current minimum value
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  • If current element is smaller than min, update the min value
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  • Return an object containing both max and min values
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Steps to solve by this approach:

 Step 1: Check if the array is empty and handle the edge case appropriately.
 Step 2: Initialize both max and min variables with the first element of the array.
 Step 3: Start a loop from index 1 (second element) to the end of the array.
 Step 4: For each element, compare it with the current maximum value.
 Step 5: If the current element is greater than max, update the max variable.
 Step 6: Compare the same element with the current minimum value.
 Step 7: If the current element is smaller than min, update the min variable.
 Step 8: Continue this process for all remaining elements.
 Step 9: Return an object containing both the maximum and minimum values found.

Submitted Code :