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Valid Anagram

Certification: Basic Level Accuracy: 62.96% Submissions: 27 Points: 5

Write a Java program to check if two strings are anagrams of each other.

Example 1
    

  • Input: s = "listen", t = "silent"
    • 

  • Output: true
    • 

  • Explanation:

      

    • Same characters with same frequencies
      • 

    

    •
Example 2
    

  • Input: s = "hello", t = "world"
    • 

  • Output: false
    • 

  • Explanation:

      

    • Different character sets and frequencies
      • 

    

    •
Constraints
    

  • 1 ≤ s.length, t.length ≤ 5 * 10^4
    • 

  • s and t consist of lowercase English letters
    • 

  • Time Complexity: O(n)
    • 

  • Space Complexity: O(1)
    •
StringsAccentureDeloitte
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Hint
Solution

Solution Hints

    
  
  • Consider that anagrams must have the same characters with the same frequency
    • 
  
  • You can use an array of size 26 to count the frequency of each character in both strings
    • 
  
  • Remember to check if the lengths of both strings are equal first
    • 
  
  • A frequency table or hash map can be used to count occurrences of each character
    •

Steps to solve by this approach:

 Step 1: Check if the lengths of both strings are equal. If not, they cannot be anagrams.
 Step 2: Create a frequency array of size 26 (for lowercase English letters).
 Step 3: Increment the count for each character in the first string.
 Step 4: Decrement the count for each character in the second string.
 Step 5: If any count becomes negative during step 4, return false.
 Step 6: If we complete the process without returning false, return true.
 Step 7: Time complexity is O(n) where n is the length of the strings.

Submitted Code :