
Problem
Solution
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K Consecutive Bit Flips
Certification: Advanced Level
Accuracy: 100%
Submissions: 1
Points: 15
Given a binary array nums
and an integer k
, you need to flip the values of k
consecutive bits starting at various indices until all values in the array become 1. A flip operation changes 0s to 1s and 1s to 0s. Return the minimum number of k-bit flips required to make all values in nums
equal to 1, or return -1 if it's not possible.
Example 1
- Input: nums = [0,1,0], k = 2
- Output: 2
- Explanation:
Step 1: Flip starting at index 0: [0,1,0] → [1,0,0]
Step 2: Flip starting at index 1: [1,0,0] → [1,1,1]
Step 3: All elements are now 1, so we needed 2 flips.
Example 2
- Input: nums = [1,1,0], k = 2
- Output: -1
- Explanation:
Step 1: If we flip starting at index 0: [1,1,0] → [0,0,0]
Step 2: If we flip starting at index 1: [1,1,0] → [1,0,1]
Step 3: In neither case can we make all elements 1 with flips of size 2.
Step 4: Therefore, it's not possible to make all elements 1 with flips of size 2.
Constraints
- 1 ≤ nums.length ≤ 10^5
- 1 ≤ k ≤ nums.length
- nums[i] is either 0 or 1
- Time Complexity: O(n)
- Space Complexity: O(n) or O(1) with optimization
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Solution Hints
- Process the array from left to right.
- If the current element is 0, you must flip k consecutive bits starting at this position.
- Keep track of flips that have already been made and their effect on current position.
- Use a greedy approach, flipping as early as possible.
- Consider using a queue or array to track where flips have been made.