// Brute force approach with multiple queries
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct {
    int week;
    char membership[10];
    int total;
} Result;

int executeQuery(const char* query) {
    // Simulate database query execution
    return 0;
}

int compareResults(const void* a, const void* b) {
    const Result* ra = (const Result*)a;
    const Result* rb = (const Result*)b;
    if (ra->week != rb->week) {
        return ra->week - rb->week;
    }
    return strcmp(ra->membership, rb->membership);
}

void bruteForceFridayAnalysis() {
    char fridays[][12] = {"2023-11-03", "2023-11-10", "2023-11-17", "2023-11-24"};
    char memberships[][10] = {"Premium", "VIP"};
    Result results[8];
    int resultCount = 0;
    
    for (int week = 0; week < 4; week++) {
        for (int m = 0; m < 2; m++) {
            char query[256];
            snprintf(query, sizeof(query),
                "SELECT COALESCE(SUM(p.amount_spend), 0) as total "
                "FROM Purchases p JOIN Users u ON p.user_id = u.user_id "
                "WHERE p.purchase_date = '%s' AND u.membership = '%s'",
                fridays[week], memberships[m]
            );
            
            int total = executeQuery(query);
            results[resultCount].week = week + 1;
            strcpy(results[resultCount].membership, memberships[m]);
            results[resultCount].total = total;
            resultCount++;
        }
    }
    
    qsort(results, resultCount, sizeof(Result), compareResults);
    
    for (int i = 0; i < resultCount; i++) {
        printf("%d %s %d\n", results[i].week, results[i].membership, results[i].total);
    }
}