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Sum of all even numbers in an array

Certification: Basic Level Accuracy: 51.28% Submissions: 39 Points: 5

Write a C# program to find the sum of all even numbers in a given integer array. The program should iterate through the array, identify even numbers, and compute their sum.

Example 1
    
  
  • Input: arr = [1, 2, 3, 4, 5, 6]
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  • Output: 12
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  • Explanation: 
    
      
      
    • Step 1: Initialize a sum variable to 0.
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    • Step 2: Iterate through each element in the array.
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    • Step 3: Check if each element is even (divisible by 2).
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    • Step 4: For even numbers (2, 4, 6), add them to the sum.
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    • Step 5: Return the final sum: 2 + 4 + 6 = 12.
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Example 2
    
  
  • Input: arr = [7, 9, 11, 13]
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  • Output: 0
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  • Explanation: 
    
      
      
    • Step 1: Initialize a sum variable to 0.
      • 
      
    • Step 2: Iterate through each element in the array.
      • 
      
    • Step 3: Check if each element is even (divisible by 2).
      • 
      
    • Step 4: No even numbers are found in the array.
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    • Step 5: Return the sum, which remains 0.
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Constraints
    
  
  • 1 ≤ array length ≤ 10^5
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  • -10^9 ≤ array elements ≤ 10^9
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  • Time Complexity: O(N)
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  • Space Complexity: O(1)
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Hint
Solution

Solution Hints

    
  
  • Iterate Through Array: Loop through all elements of the array.
  • Check Even Numbers: Use num % 2 == 0 to identify even numbers.
  • Sum Calculation: Add even numbers to a running sum.
  • Edge Case: Handle cases where no even numbers exist (return 0).
    •

Steps to Solve:

The following are the steps to find the sum of all even numbers in an array:

    
  
  • Initialize a sum variable to 0.
    • 
  
  • Iterate through each element in the array.
    • 
  
  • Check if each element is even (divisible by 2):
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    • Use the modulo operator (%) to check if the number divides evenly by 2.
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    • If arr[i] % 2 == 0, the number is even.
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  • If the element is even, add it to the sum.
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  • After iterating through all elements, return the final sum.
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Submitted Code :