Problem
Solution
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if a Year is a Leap Year
Certification: Basic Level
Accuracy: 40%
Submissions: 5
Points: 5
Write a C# program to implement the IsLeapYear(int year) function, which determines whether a given year is a leap year according to the Gregorian calendar rules.
Algorithm
- Step 1: A year is a leap year if it is divisible by 4.
- Step 2: However, if the year is divisible by 100, it is NOT a leap year, unless:
- Step 3: The year is also divisible by 400, in which case it IS a leap year.
Example 1
- Input: year = 2000
- Output: true
- Explanation:
- 2000 is divisible by 4 (2000 ÷ 4 = 500 with remainder 0).
- 2000 is divisible by 100 (2000 ÷ 100 = 20 with remainder 0).
- 2000 is divisible by 400 (2000 ÷ 400 = 5 with remainder 0).
- According to leap year rules, since it's divisible by 400, it is a leap year.
Example 2
- Input: year = 1900
- Output: false
- Explanation:
- 1900 is divisible by 4 (1900 ÷ 4 = 475 with remainder 0).
- 1900 is divisible by 100 (1900 ÷ 100 = 19 with remainder 0).
- 1900 is NOT divisible by 400 (1900 ÷ 400 = 4 with remainder 300).
- According to leap year rules, since it's divisible by 100 but not by 400, it is NOT a leap year.
Constraints
- 1 ≤ year ≤ 9999
- The input will be a positive integer representing a year in the Gregorian calendar.
- Time Complexity: O(1)
- Space Complexity: O(1)
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Solution Hints
- Use the modulo operator (%) to check divisibility.
- Remember that a year divisible by 4 might not be a leap year if it's divisible by 100.
- But if it's divisible by 400, it's always a leap year regardless of other rules.
- Consider the order of your conditional checks for clarity.