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							Count and Say Sequence
								Certification: Basic Level
								Accuracy: 0%
								Submissions: 0
								Points: 5
							
							Write a C program to generate the nth term of the "Count and Say" sequence. The "Count and Say" sequence is a sequence of digit strings defined by the recursive formula:
- countAndSay(1) = "1"
- countAndSay(n)is the way you would "say" the digit string from- countAndSay(n-1), which is then converted into a different digit string.
To determine how you "say" a digit string, split it into the minimal number of substrings such that each substring contains exactly one unique digit. Then for each substring, say the number of digits, followed by the digit. Finally, concatenate every said digit.
For example, the saying and conversion for digit string "3322251":
Two 3's, three 2's, one 5, and one 1 becomes "23321511".
Example 1
- Input: n = 1
- Output: "1"
- Explanation:
 Step 1: countAndSay(1) = "1" (base case)
Example 2
- Input: n = 4
- Output: "1211"
- Explanation:
 Step 1: countAndSay(1) = "1" (base case)
 Step 2: countAndSay(2) = say "1" = one 1 = "11"
 Step 3: countAndSay(3) = say "11" = two 1's = "21"
 Step 4: countAndSay(4) = say "21" = one 2 followed by one 1 = "1211"
Constraints
- 1 ≤ n ≤ 30
- The answer string will only contain digits
- Time Complexity: O(2^n) - since the length of the result can grow exponentially
- Space Complexity: O(2^n) - to store the result string
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Solution Hints
- Use a recursive approach or an iterative approach to generate the sequence
- For each iteration, generate the next term by reading the previous term
- Use two pointers or a counter to track consecutive identical digits
- Build the result string by concatenating the count and the digit
- Handle the base case separately (when n = 1)
