Angle Between Hands of a Clock - Problem
Given two integers hour and minutes, return the smaller angle (in degrees) formed between the hour and minute hands on a clock.
The angle should be calculated as a positive floating-point number. Answers within 10^-5 of the actual value will be accepted as correct.
Note: The hour hand moves continuously as minutes pass, not in discrete jumps.
Input & Output
Example 1 — Basic Case
$
Input:
hour = 12, minutes = 30
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Output:
165.0
💡 Note:
At 12:30, minute hand points to 6 (180°), hour hand is halfway between 12 and 1 (15°). Angle = |180° - 15°| = 165°
Example 2 — Perfect Alignment
$
Input:
hour = 3, minutes = 0
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Output:
90.0
💡 Note:
At 3:00, minute hand points to 12 (0°), hour hand points to 3 (90°). Angle = |90° - 0°| = 90°
Example 3 — Obtuse Angle Case
$
Input:
hour = 3, minutes = 30
›
Output:
75.0
💡 Note:
At 3:30, minute hand at 180°, hour hand at 105° (3×30° + 30×0.5°). Angle = |180° - 105°| = 75°
Constraints
- 1 ≤ hour ≤ 12
- 0 ≤ minutes ≤ 59
Visualization
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Explanation
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