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$PQRS$ is a parallelogram $(Fig 11.23)$. $QM$ is the height from $Q$ to $SR$ and $QN$ is the height from $Q$ to $PS$. If $SR = 12\ cm$ and $QM = 7.6\ cm$. Find:
$(a)$ the area of the parallegram $PQRS$
$(b)$ $QN$
$(a)$. $SR = 12\ cm$ and $QM = 7.6\ cm$
Area of parallelogram $PQRS = Base\times Height$
$= SR\times QM$
$= 12\ cm\times 7.6\ cm$
$= 91.2 cm^2$
$(b)$. Base $= PS = 8\ cm$
Area of the parallelogram $= 91.2\ cm^2$ [calculated in part $(a)$]
Area of parallelogram $PQRS = Base\times Height$
$91.2\ cm^2 = 8 cm\times QN$
$QN = 91.2\ cm^2 / 8 cm$
$QN = 11.4\ cm$
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