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# Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation.

**(a)** $ 5 m=60 $ $ (10,5,12,15) $

**(b)** $ n+12=20 $ $ (12,8,20,0) $

**(c)** $ p-5=5 $ $ (0,10,5-5) $

**(d)** $ \frac{q}{2}=7 $ $ (7,2,10,14) $

**(e)** $ r-4=0 $ $ (4,-4,8,0) $

**(f)** $ x+4=2 $ $ (-2,0,2,4) $

To do:

We have to pick out the solution from the values given in the bracket next to each equation.

Solutions:

(a) $5m = 60$

If $m = 10$ then $5m=5(10)=50$

$m=10$ is not a solution for the equation $5m = 60$

Therefore, the equation is not satisfied.

If $m = 5$ then $5m=5(5)=25$

$m=5$ is not a solution for the equation $5m = 60$

Therefore, the equation is not satisfied.

If $m = 12$ then $5m=5(12)=60$

$m=12$ is a solution for the equation $5m = 60$

Therefore, the equation is satisfied.

If $m = 15$ then $5m=5(15)=75$

$m=15$ is not a solution for the equation $5m = 60$

Therefore, the equation is not satisfied.

(b) $n + 12 = 20$

If $n = 12$ then $n+12=12+12=24$

$n=12$ is not a solution for the equation $n+12 = 20$

Therefore, the equation is not satisfied.

If $n = 8$ then $n+12=8+12=20$

$n=8$ is a solution for the equation $n+12 = 20$

Therefore, the equation is satisfied.

If $n = 20$ then $n+12=20+12=32$

$n=20$ is not a solution for the equation $n+12 = 20$

Therefore, the equation is not satisfied.

If $n = 0$ then $n+12=0+12=12$

$n=0$ is not a solution for the equation $n+12 = 20$

Therefore, the equation is not satisfied.

(c) $p - 5 = 5$

If $p = 0$ then $p-5=0-5=-5$

$p=0$ is not a solution for the equation $p-5 = 5$

Therefore, the equation is not satisfied.

If $p = 10$ then $p-5=10-5=5$

$p=10$ is a solution for the equation $p-5 = 5$

Therefore, the equation is satisfied.

If $p = 5$ then $p-5=5-5=0$

$p=5$ is not a solution for the equation $p-5 = 5$

Therefore, the equation is not satisfied.

If $p = -5$ then $p-5=-5-5=-10$

$p=-5$ is not a solution for the equation $p-5 = 5$

Therefore, the equation is not satisfied.

(d) $\frac{q}{2} = 7$

If $q = 7$ then $\frac{q}{2}=\frac{7}{2}$

$q=7$ is not a solution for the equation $\frac{q}{2} = 7$

Therefore, the equation is not satisfied.

If $q = 2$ then $\frac{q}{2}=\frac{2}{2}=1$

$q=2$ is not a solution for the equation $\frac{q}{2} = 7$

Therefore, the equation is not satisfied.

If $q = 10$ then $\frac{q}{2}=\frac{10}{2}=5$

$q=10$ is not a solution for the equation $\frac{q}{2} = 7$

Therefore, the equation is not satisfied.

If $q = 14$ then $\frac{q}{2}=\frac{14}{2}=7$

$q=14$ is a solution for the equation $\frac{q}{2} = 7$

Therefore, the equation is satisfied.

(e) $r - 4 = 0$

If $r = 4$ then $r-4=4-4=0$

$r=4$ is a solution for the equation $r-4 = 0$

Therefore, the equation is satisfied.

If $r = -4$ then $r-4=-4-4=-8$

$r=-4$ is not a solution for the equation $r-4 = 0$

Therefore, the equation is not satisfied.

If $r = 8$ then $r-4=8-4=4$

$r=8$ is not a solution for the equation $r-4 = 0$

Therefore, the equation is not satisfied.

If $r = 0$ then $r-4=0-4=-4$

$r=0$ is not a solution for the equation $r-4 = 0$

Therefore, the equation is not satisfied.

(f) $x + 4 = 2$

If $x = -2$ then $x+4=-2+4=2$

$x=-2$ is a solution for the equation $x+4 = 2$

Therefore, the equation is satisfied.

If $x = 0$ then $x+4=0+4=4$

$x=0$ is not a solution for the equation $x+4 = 2$

Therefore, the equation is not satisfied.

If $x = 2$ then $x+4=2+4=6$

$x=2$ is not a solution for the equation $x+4 = 2$

Therefore, the equation is not satisfied.

If $x = 4$ then $x+4=4+4=8$

$x=4$ is not a solution for the equation $x+4 = 2$

Therefore, the equation is not satisfied.

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