Write the ratio in the simplest form (lowest terms).
(i) $ 600 \mathrm{~g} $ to $ 1 \mathrm{~kg} $
(ii) $ 50 \mathrm{p} $ to $ Rs. 2.50 $
(iii) $ 2 \mathrm{~L} $ to $ 800 \mathrm{~mL} $
(iv) $ 80 \mathrm{~cm} $ to $ 4 \mathrm{~m} $
Given:
(i) \( 600 \mathrm{~g} \) to \( 1 \mathrm{~kg} \)
(ii) 50 paise to \( Rs. 2.50 \)
(iii) 2 L to 800 mL
(iv) \( 80 \mathrm{~cm} \) to \( 4 \mathrm{~m} \)
To do:
Here, we have to express the given ratios in the simplest form.
Solution:
We know that;
$1\ m = 100\ cm$
$1\ kg=1000\ g$
$1\ L=1000\ mL$
$Rs.\ 1=100\ paise$
(i) $600\ g:1\ kg=600:1\times1000$
$=600:1000$
$=3:5$
(ii) $50\ paise: Rs.\ 2.50=50:2.50\times100$
$=50:250$
$1:5$
(iii) $2\ L:800\ mL=2\times1000:800$
$=2000:800$
$=5:2$
(iv) $80\ cm:4\ m=80:4\times100$
$=80:400$
$=1:5$
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