Write the ratio in the simplest form (lowest terms).
(i) \( 600 \mathrm{~g} \) to \( 1 \mathrm{~kg} \)
(ii) \( 50 \mathrm{p} \) to \( Rs. 2.50 \)
(iii) \( 2 \mathrm{~L} \) to \( 800 \mathrm{~mL} \)
(iv) \( 80 \mathrm{~cm} \) to \( 4 \mathrm{~m} \)

Academic Mathematics NCERT Class 6

Given:

(i) \( 600 \mathrm{~g} \) to \( 1 \mathrm{~kg} \)

(ii) 50 paise to \( Rs. 2.50 \)

(iii) 2 L to 800 mL

(iv) \( 80 \mathrm{~cm} \) to \( 4 \mathrm{~m} \)

To do:

Here, we have to express the given ratios in the simplest form.

Solution:

We know that;

$1\ m = 100\ cm$

$1\ kg=1000\ g$

$1\ L=1000\ mL$

$Rs.\ 1=100\ paise$

(i) $600\ g:1\ kg=600:1\times1000$

$=600:1000$

$=3:5$

(ii) $50\ paise: Rs.\ 2.50=50:2.50\times100$

$=50:250$

$1:5$

(iii) $2\ L:800\ mL=2\times1000:800$

$=2000:800$

$=5:2$

(iv) $80\ cm:4\ m=80:4\times100$

$=80:400$

$=1:5$

Updated on: 10-Oct-2022

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