Write the discriminant of the following quadratic equations:
$(x-1)(2x-1)= 0$

Given:

Given quadratic equation is $(x-1)(2x-1)= 0$.

To do:

We have to find the discriminant of the given quadratic equation.

Solution:

$(x-1)(2x-1)= 0$

$2x^2-x-2x+1=0$

$2x^2-3x+1=0$

Comparing the given quadratic equation with the standard form of the quadratic equation $ax^2+bx+c=0$, we get,

$a=2, b=-3$ and $c=1$.

The discriminant of the standard form of the quadratic equation $ax^2+bx+c=0$ is $D=b^2-4ac$.

Therefore,

$D=(-3)^2-4(2)(1)=9-8=1$.

The discriminant of the given quadratic equation is $1$.

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Updated on: 10-Oct-2022

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