Write the IUPAC name of the following :(i) CH₃COCH₃    (ii) CH₃COCH₂CH₃

(i) As there are 3 carbons (prop) present and the functional group present is a ketone. Therefore, the IUPAC name is  Propanone.

(ii) As there are 4 carbons (but) present and the functional group present is a ketone. Therefore, the IUPAC name is Butanone.