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With the help of a labelled ray diagram, describe how a converging mirror can be used to give an enlarged upright image of an object.
For obtaining an enlarged upright image of an object, the object is placed between the focus $(F)$ and pole $(P)$ of the converging mirror (concave mirror).
A ray $AD$ parallel to the principal axis gets reflected at $D$ and then passes through the focus $F$. A second ray $AE$ passing through the centre of curvature $C$ strikes the mirror normally at point $E$ and gets reflected back along the same path.
Now, two reflected rays $DF$ and $EC$ are diverging rays and, therefore, do not intersect each other on the left side. The reflected rays $DF$ and $EC$ are produced backwards (as shown by dotted lines). On producing backwards (behind the mirror), they appear to intersect at point $A’$. Thus, $A’$ is the virtual image of point $A$ of the object. To get the complete image of the object we draw $A’B’$ perpendicular to the axis. Thus, $A’B’$ is the image of the object $AB$ obtained by the concave mirror. The image is bigger in size than the object, hence it is a magnified or enlarged image.