While covering a distance of 30 km. Ajeet takes 2 hours more than Amit. If Ajeet doubles his speed, he would take 1 hour less than Amit. Find their speeds of walking.
Given:
While covering a distance of 30 km, Ajeet takes 2 hours more than Amit. If Ajeet doubles his speed, he would take 1 hour less than Amit.
To do:
We have to find the speeds of their walking.
Solution:
Total distance $= 30\ km$
Let the speed of Ajeet be $x\ km/hr$ and the speed of Amit be $y\ km/hr$.
We know that,
$Time=\frac{Distance}{Speed}$
According to the question,
While covering a distance of 30 km, Ajeet takes 2 hours more than Amit.
This implies,
$\frac{30}{x}=\frac{30}{y}+2$
$\frac{30}{x}-\frac{30}{y}=2$......(i)
If Ajeet doubles his speed, he would take 1 hour less than Amit.
This implies,
$\frac{30}{2x}=\frac{30}{y}-1$
$\frac{15}{x}-\frac{30}{y}=-1$......(ii)
Subtracting equation (ii) from equation (i), we get,
$\frac{30}{x}-\frac{30}{y}-\frac{15}{x}+\frac{30}{y}=2-(-1)$
$\frac{30-15}{x}=2+1$
$\frac{15}{x}=3$
$x=\frac{15}{3}$
$x=5$
Substituting the value of $x=5$ in equation (i), we get,
$\frac{30}{5}-\frac{30}{y}=2$
$6-2=\frac{30}{y}$
$y=\frac{30}{4}$
$y=7.5$
The speed of Ajeet is $5\ km/hr$ and the speed of Amit is $7.5\ km/hr$.
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