Which term of the A.P. $84, 80, 76, …..$ is $0$?

Given:

Given A.P. is $84, 80, 76, …..$

To do:

We have to find $0$ is which term of the given A.P.

Solution:

Let $0$ be the nth term of the given A.P.

Here,

$a_1=84, a_2=80, a_3=76$

Common difference $d=a_2-a_1=80-84=-4$

We know that,

nth term $a_n=a+(n-1)d$

Therefore,

$a_{n}=84+(n-1)(-4)$

$0=84+n(-4)-1(-4)$

$0-84=-4n+4$

$84+4=4n$

$4n=88$

$n=\frac{88}{4}$

$n=22$

Hence, $0$ is the 22nd term of the given A.P.  

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Updated on: 10-Oct-2022

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