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Which term of the A.P. $3, 8, 13, ……$ is $248$?
Given:
Given A.P. is $3, 8, 13, ……$
To do:
We have to find $248$ is which term of the given A.P.
Solution:
Let $248$ be the nth term of the given A.P.
Here,
$a_1=3, a_2=8, a_3=13$
Common difference $d=a_2-a_1=8-3=5$
We know that,
nth term $a_n=a+(n-1)d$
Therefore,
$a_{n}=3+(n-1)(5)$
$248=3+n(5)-1(5)$
$248-3=5n-5$
$245+5=5n$
$5n=250$
$n=\frac{250}{5}$
$n=50$
Hence, $248$ is the 50th term of the given A.P.  
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