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Which term of the A.P. $21, 42, 63, 84, …..$ is $420$?
Given:
Given A.P. is $21, 42, 63, 84, …..$
To do:
We have to find $420$ is which term of the given A.P.
Solution:
Let $420$ be the nth term of the given A.P.
Here,
$a_1=21, a_2=42, a_3=63$
Common difference $d=a_2-a_1=42-21=21$
We know that,
nth term $a_n=a+(n-1)d$
Therefore,
$a_{n}=21+(n-1)(21)$
$420=21+n(21)-1(21)$
$420-21=21n-21$
$420=21n$
$n=\frac{420}{21}$
$n=20$
Hence, $420$ is the 20th term of the given A.P.    
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