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Which one of the following options is true, and why? $ y=3 x+5 $ has
(i) a unique solution,
(ii) only two solutions,
(iii) infinitely many solutions.
To do:
We have to find which one of the given options is true and why.
Solution:
Let us substitute $x=0$ in the given equation $y= 3x+5$
We get,
$y=3(0)+5$
$y=0+5$
$y=5$
If we substitute $x=1$
We get,
$y=3(1)+5$
$y=3+5$
$y=8$
In the similar way,
If we substitute $x=2,3,4,5.......$
We get,
$x$ | $y=3x+5$ |
2 | $y=3(2)+5=6+5=11$ |
3 | $y=3(3)+5=9+5=14$ |
4 | $y=3(4)+5=12+5=17$ |
..... | ....... |
Therefore,
From the table we can observe that for infinite values of x, we can get infinite values of y.
Hence, $y=3x+5$ has infinitely many solutions.
Therefore,
From the given options, (iii) is True.
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