Which of these $123^2, 77^2, 82^2, 161^2, 109^2$ would ends with the digit one?

Given :

Given numbers are  $123^2, 77^2, 82^2, 161^2, 109^2$

To find :

We have to find the the numbers that ends with digit 1 among the given numbers.

Solution :

We know that,

If a number has 1 or 9 in the unit’s place, then its square ends in 1.

Among the given numbers 161 and 109 end with 1 and 9.

Therefore, $161^2$ and $109^2$ will end with digit one.

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Updated on: 10-Oct-2022

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