Which of the following is the exponential form of the expression given below?
$( \frac{-2}{7})^7\p( \frac{-2}{7})^5$

Given: $( \frac{-2}{7})^7\div( \frac{-2}{7})^5$

To do: To find the exponential form of the given expression.

Solution:

$( \frac{-2}{7})^7\div( \frac{-2}{7})^5$

$=( \frac{-2}{7})^{7-5}$                                         [$\because a^m-a^n=a^{m-n}$]

$=( \frac{-2}{7})^2$

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Updated on: 10-Oct-2022

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