Which of the following is a proper fraction in its simplest form whose denominator is 6 more than the numerator?

A) $\frac{2}{8}$

B) $\frac{1}{7}$

C) $\frac{3}{9}$

D) $\frac{4}{11}$

Given A) $\frac{2}{8}$, B) $\frac{1}{7}$, C) $\frac{3}{9}$, D) $\frac{4}{11}$

To find proper fraction in its simplest form whose denominator is 6 more than the numerator

Solution

It is $\frac{1}{7}$. The option B) $\frac{1}{7}$ is CORRECT. It is the proper fraction that is in the simplest form where the denominator is 6 more than the numerator. 
 

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Updated on: 10-Oct-2022

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