Which of the following are quadratic equations?

$2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$

Given:

Given quadratic equation is $2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$.

To do:

We have to check whether the given equation is quadratic.

Solution:

The standard form of a quadratic equation is $ax^2+bx+c=0$.

$2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$

The equation $2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$ is not of the form $ax^2+bx+c=0$ as the power of $\sqrt{3x}$ is not an integer.

Therefore, $2x^2\ -\ \sqrt{3x}\ +\ 9\ =\ 0$ is not a quadratic equation.

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Updated on: 10-Oct-2022

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