Where will be the hand of a clock stop if it starts at 5 and makes 3/4 of revolution, clockwise?
Given: The hand of a clock stop if it starts at 5 and makes 3/4 of revolution, clockwise.
To find: We have to find the number at which the hand of the clock stops
Solution:
Number of hours in 1 revolution = 12 hours
Number of hours in $\frac{3}{4}$ revolution = 12 x $\frac{3}{4}$ = 9 hours
So the hand will move 9 hours and stop at 2.
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