When speed of the moving object is doubled its:
  1. Acceleration is doubled
  2. Momentum becomes four times more
  3. K E. is increased to four times
  4. Potential energy is increased

Let $v$ be the velocity of the moving object.

Kinetic energy of the moving body $K_1=\frac{1}{2}mv^2$

When the speed of a moving object is doubled, it becomes $2v$

Then kinetic energy $K_2=\frac{1}{2}m(2v)^2$



Therefore, on doubling the speed of a moving object, the kinetic energy becomes four times.

Therefore, option c is correct.


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