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# When speed of the moving object is doubled its:- Acceleration is doubled
- Momentum becomes four times more
- K E. is increased to four times
- Potential energy is increased

Let $v$ be the velocity of the moving object.

Kinetic energy of the moving body $K_1=\frac{1}{2}mv^2$

When the speed of a moving object is doubled, it becomes $2v$

Then kinetic energy $K_2=\frac{1}{2}m(2v)^2$

$=4\times\frac{1}{2}mv^2$

$=4K_1$

Therefore, on doubling the speed of a moving object, the kinetic energy becomes four times.

Therefore, option **c **is correct.

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