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When $a=0$, $b=1$ find the value of the given expressions:
$(i)$. $2a+2b$
$(ii)$. $2a^2+b^2+1$
$(iii)$. $2a^2b+2ab^2+ab$
$(iv)$. $a^2+ab+2$
Given:
$(i)$. $2a+2b$
$(ii)$. $2a^2+b^2+1$
$(iii)$. $2a^2b+2ab^2+ab$
$(iv)$. $a^2+ab+2$
To do: To find the value of the given expressions when $a=0$, $b=-1$.
Solution:
$(i)$. $2a+2b$
Putting $a=0$ and $b=-1$
$=2(0)+2(-1)$
$=0-2$
$=-2$
$(ii)$. $2a^2+b^2+1$
Putting $a=0$ and $b=-1$
$=2(0)^2+(-1)^2+1$
$=0+1+1$
$=2$
$(iii)$. $2a^2b+2ab^2+ab$
Putting $a=0$ and $b=-1$
$=2(0)^2(-1)+2(0)(-1)^2+0(-1)$
$=0+0+0$
$=0$
$(iv)$. $a^2+ab+2$
Putting $a=0$ and $b=-1$
$=0^2+(0)(-1)+2$
$=0+0+2$
$=2$
Updated on: 10-Oct-2022
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