What should be taken away from (6m² $-$ 4n² $+$ 3mn $+$ 15) to obtain ($-$m² $-$ n² $+$ 3mn $+$ 15)?

Given: (6m2 $-$ 4n2 $+$ 3mn $+$ 15) and ($-$m2 $-$ n2 $+$ 3mn $+$ 15).

To find: What should be taken away from (6m2 $-$ 4n2 $+$ 3mn $+$ 15) to obtain ($-$m2 $-$ n2 $+$ 3mn $+$ 15)?

Solution:

Let the required value be = a

So,

(6m2 $-$ 4n2 $+$ 3mn $+$ 15) $-$ a = ($-$m2 $-$ n2 $+$ 3mn $+$ 15)

(6m2 $-$ 4n2 $+$ 3mn $+$ 15) $-$ ($-$m2 $-$ n2 $+$ 3mn $+$ 15) = a

6m2 $-$ 4n2 $+$ 3mn $+$ 15 $+$ m2 $+$ n2 $-$ 3mn $-$ 15 = a

7m2 $-$ 3n2 = a

Therefore, (7m2 $-$ 3n²)  should be taken away from (6m2 $-$ 4n2 $+$ 3mn $+$ 15) to obtain ($-$m2 $-$ n2 $+$ 3mn $+$ 15).

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Updated on: 10-Oct-2022

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