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What should be added to $\frac{-7}{8}$ so as to get $\frac{5}{9}$?
Given :
The given numbers are $\frac{-7}{8}$ and $\frac{5}{9}$.
To do :
We have to find the number that should be added to $\frac{-7}{8}$ to get $\frac{5}{9}$.
Solution :
Let the number to be added to $\frac{-7}{8}$ to get $\frac{5}{9}$ be $x$.
This implies,
$\frac{-7}{8}+x=\frac{5}{9}$
$x =\frac{5}{9} - (\frac{-7}{8})$
$x =\frac{5}{9} + \frac{7}{8}$
$x = \frac{[5(8)+7(9)]}{72}$
$x = \frac{(40+63)}{72}$
$x = \frac{103}{72}$.
The number to be added to $\frac{-7}{8}$ to get $\frac{5}{9}$ is $\frac{103}{72}$.
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