What must be subtracted from $5 \frac{1}{6}$ to get $2 \frac{11}{18}$ ?

Given :

The given fractions are $5 \frac{1}{6}$ and $2 \frac{11}{18}$ 

To do :

We have to find what must be subtracted from $5 \frac{1}{6}$ to get $2 \frac{11}{18}$ .

Solution :

Let the number to be subtracted from from $5 \frac{1}{6}$ to get $2 \frac{11}{18}$ be x.

$5 \frac{1}{6} = \frac{(5\times 6+1)}{6} = \frac{(30+1)}{6} = \frac{31}{6}$

$2 \frac{11}{18} = \frac{(2\times 18+11)}{18} = \frac{(36+11)}{18} = \frac{47}{18}$

Therefore,

$5 \frac{1}{6}  - x =  \frac{11}{18}$

 $ \frac{31}{6} - x = \frac{47}{18}$

$x = \frac{31}{6}- \frac{47}{18}$

$x = \frac{(31\times 3-47)}{18}$

$x = \frac{(93-47)}{18}$

$x = \frac{46}{18}$

$x = \frac{23}{9}$

Therefore,

$\frac{23}{9}$ must be subtracted from $5 \frac{1}{6}$ to get $2 \frac{11}{18}$ .

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Updated on: 10-Oct-2022

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