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What must be added to the numbers 6,10,14 and 22 so that they are in proportion?
Given :
The given numbers are 6, 10, 14, and 22.
To do :
We have to find the number that should be added to the given numbers so that they are in proportion.
Solution :
Let the number to be added be 'x'.
So, the numbers $6+x, 10+x, 14+x, 22+x$ are in proportion.
Product of extremes $=$ Product of means
$(6+x)(22+x)=(10+x)(14+x)$
$132 + 22x + 6x + x^2 = 140 + 10x + 14x + x^2$
$132+28x = 140+24x$
$28x-24x = 140-132$
$4x = 8$
$x= \frac{8}{4}$
$x=2$
Therefore, the required number is 2.
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