What is the probability of getting $53$ Mondays in a leap year?

Given: $53$ Mondays in a leap year.

To do: To find the probability of getting $53$ Mondays in a leap year.

$1$ year$=365$ days

A leap year has $366$ days

A year has $52$ weeks. Hence there will be $52$ Mondays for sure.

$52$ weeks$=52\times7 = 364$ days

$366-364=2$ days

In a leap year there will be $52$ Mondays and $2$ days will be left.

These $2$ days can be:

Sunday, Monday

Monday, Tuesday

Tuesday, Wednesday

Wednesday, Thursday

Thursday, Friday

Friday, Saturday

Saturday, Sunday

Of these total $7$ outcomes, the favourable outcomes are $2$.

Hence the probability of getting $53$ Mondays in a leap year is $\frac{2}{7}$.