What is the mass of $5\ m^3$ of cement of density $3000\ kg/m^3$ ?

Here given, volume of the cement $=5\ m^3$

Density of the cement $=3000\ kg/m^3$

Let $m$ be the mass of the cement.

As known, $density=\frac{mass}{volume}$

Or $3000\ kg/m^3=\frac{m}{5\ m^3}$

Or $m=3000\times5$

Or $m=15000\ kg$

Therefore, mass of the cement is $15000\ kg$.

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Updated on: 10-Oct-2022

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