What is the change in momentum of a car weighing 1500 kg when its speed increases from 36 km/h to 72 km/h uniformly ?

 Here given, the mass of the car $m=1500\ kg$

Initial velocity $v_1=36\ km/h=36\times\frac{5}{18}\ m/s=10\ m/s$

Final velocity $v_2=72\ km/h=72\times\frac{5}{18}\ m/s=20\ m/s$

Therefore, change of momentum $=mv_2-mv_1$

$=m(v_2-v_1)$

$=1500\ kg(20\ m/s-10\ m/s)$

$=1500\ kg\times 10\ m/s$

$=15000\ kg-m/s$

Therefore, the change in momentum is $15000\ kg-m/s$ when the speed of a $1500\ kg$ weighing car increases from 36 km/h to 72 km/h uniformly.

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Updated on: 10-Oct-2022

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