What is the area of triangle, parallelogram, and trapezium?

Academic Mathematics NCERT Class 8

$\begin{array}{l}Area\ of\ triangle\ =\ \frac{1}{2} \ \times \ Base\ \times \ Height\\\\\\Area\ of\ triangle\ =\ \frac{1}{2} \ \times \ b\ \times \ h\end{array}$

$1) A r e a o f t r i a n g l e = 21 \times B a s e \times H e i g h t A r e a o f t r i a n g l e = 21 \times b \times h $

$2) Area of parallelogram = Base \times Height$

$Area of parallelogram = b \times h$

$\begin{array}{l}Area\ of\ Trapezium\ =\ \frac{1}{2} \ \times \ ( Sum\ of\ parallel\ sides) \ \times \ Distance\ between\ parallel\ sides\\\\\\Area\ of\ Trapezium\ =\ \frac{1}{2} \ \times \ ( a\ +\ b) \ \times \ h\end{array}$

$3) A r e a o f T r a p e z i u m = 21 \times (S u m o f p a r a l l e l s i d e s) \times D i s t a n c e b e t w e e n p a r a l l e l s i d e s A r e a o f T r a p e z i u m = 21 \times (a + b) \times h $

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Updated on: 10-Oct-2022

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