What is $5-3(-6)$?
Given:
$5-3(-6)$
To do:
We have to find the value of $5-3(-6)$.
Solution:
We know that,
$[(-)\times(-)=(+)]$
Therefore,
$5-3(-6)=5-(3\times-6)$
$=5-(-18)$
$=5+18$
$=23$
Therefore, $5-3(-6)=23$.
Related Articles
- What Is the answer Of -8/3 + -6/5
- Prove that:\( \sqrt{3 \times 5^{-3}} \p \sqrt[3]{3^{-1}} \sqrt{5} \times \sqrt[6]{3 \times 5^{6}}=\frac{3}{5} \)
- $\frac{3}{5} x\ -\ 6\ =\ 3$
- Find the mode of the following data: 3, 5, 7, 4, 5, 3, 5, 6, 8, 9, 5, 3, 5, 3, 6, 9, 7, 4.
- Find the mode of the following data: 3, 3, 7, 4, 5, 3, 5, 6, 8, 9, 5, 3, 5, 3, 6, 9, 7, 4.
- Solve:\( \frac{6-4 \sqrt{5}+3 \sqrt{5}-10}{9-6 \sqrt{5}+6 \sqrt{5}-4 \sqrt{25}} \)
- Simplify: \( \frac{7^{-5}}{5^{-3}} \times 10^{-4} \times \frac{6^{-5}}{(42)^{-6}} \)
- -5[6 ÷ 3 x (-2)] - [9 - (-5) x 2]
- What number should be subtracted from $\frac{−5}{3}$ to get $\frac{5}{6}$?
- Solve the following:$\sqrt{3\times 5^{-3} \ } \div \sqrt[3] 3^{-1} \ \sqrt{5} \ \times \acute{}\sqrt[6]{3\times 5^{5}}$
- Prove that $(4, 3), (6, 4), (5, 6)$ and $(3, 5)$ are the angular points of a square.
- Solve: $-\frac{2}{3}\ \times\ \frac{3}{5}\ +\ \frac{5}{2}\ -\ \frac{3}{5}\ \times\ \frac{1}{6}$
- Simplify:$\frac{-2}{3}\times\frac{3}{5}+\frac{5}{2}-\frac{3}{5}\times\frac{1}{6}$.
- Take away:\( \frac{6}{5} x^{2}-\frac{4}{5} x^{3}+\frac{5}{6}+\frac{3}{2} x \) from \( \frac{x^{3}}{3}-\frac{5}{2} x^{2}+\frac{3}{5} x+\frac{1}{4} \)
- Simplify:\( \frac{3^{-5} \times 10^{-5} \times 125}{5^{-7} \times 6^{-5}} \)
Kickstart Your Career
Get certified by completing the course
Get Started
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies