What are the factors of $x^2+4y^2+4y-4xy-2x-8$.

Given: $x^2+4y^2+4y-4xy-2x-8$.

To do: To find the factors of the given polynomial.

Solution:

$x^2-4xy+4y^2-2x+4y-8$

$=(x-2y)^2 -2(x-2y) -8$

$=(x-2y)[(x-2y)-2] -8$

$=(x-2y)(x-2y-2)-8$
 

Updated on: 10-Oct-2022

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