Water freezes at 0°C and boils at 100°C. Give these temperatures in °F

Given that water freezes at 0°C and boils at 100°C. 

To find these temperatures in °F.

 

Solution:

The formula to convert temperatures in degrees Celsius to degrees Fahrenheit is

F = $C\times \frac{9}{5} + 32$

So 0°C in degrees Fahrenheit is

F = $0\times \frac{9}{5} + 32$

    = $0 + 32$ = $32$

 So, 0°C    = 32°F

 100°C in degrees Fahrenheit is

F = $100\times \frac{9}{5} + 32$

    = $180 + 32$ =$212$

So, 100°C    = 212°F