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Using protractor, draw a right angle. Bisect it to get an angle of measure $45^o$.
To do:
We have to draw a right angle and bisect it to get an angle of measure $45^o$.
Solution:
Steps of construction:
(i) Using a protractor, draw a right-angled triangle $ABC$.
$\angle ABC = 90^o$.
(ii) With centre $B$ and a suitable radius, draw an arc that meets $BC$ at $E$ and $BA$ at $F$.
(iii) With centre $E$ and $F,$ draw arcs intersecting each other at $G$.
(iv) Join $BG$ and produce it to $D$.
Therefore, $BD$ is the bisector of $\angle ABC$.
This implies,
$\angle DBC =\frac{1}{2}\times90^o$
$= 45^o$.
Updated on: 10-Oct-2022
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