# Two vertical poles of height 9 m and 14 m stand on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.

__Given:__ Two vertical poles of height 9 m and 14 m stand on a plane ground and the distance between their feet is 12 m.

__To find:__ We have to find the distance between the tops of the tower

__Solution:__

In the below diagram, AB is the 9 m pole, DC is the 14 m pole and BC is the distance between their feet.

To find the value of AD first draw a line from point A to point E on side DC parallel to BC.

Now,

EC = AB = 9 m

AE = BC = 12 m

In ∆AED apply Pythagoras theorem;

AD^{2} = AE^{2} + DE^{2}

AD^{2} = 12^{2} + 9^{2}

AD^{2} = 144 + 81

AD^{2} = 225

AD = √225

**AD = 15 m**

**
**

So, the distance between their tops is 15 m.

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