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Two equal side of a triangle are each 4m less than three times the third side. Find the side of the triangle if it's perimeter is 55 m
Given:
Two equal side of a triangle are each 4 m less than three times the third side. The perimeter of the triangle is 55 m.
To do:
We have to find the length of each side of the triangle.
Solution:
Let the length of the third side be $x$.
This implies,
The length of each of the other two sides $=(3x-4)\ m$
Therefore,
$x+3x-4+3x-4=55\ m$
$7x-8=55\ m$
$7x=55+8\ m$
$x=\frac{63}{7}\ m$
$x=9\ m$
$3x-4=3(9)-4\ m=27-4=23\ m$
The lengths of the sides of the triangle are 9 m, 23 m and 23 cm.
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